%%%
% Equations
%%%
\setKVdefault[ClesEquation]{Ecart=0.5,Fleches=false,FlecheDiv=false,Laurent=false,Decomposition=false,Terme=false,Composition=false,Symbole=false,Decimal=false,Entier=false,Lettre=x,Solution=false,LettreSol=true,Bloc=false,Simplification=false,CouleurTerme=black,CouleurCompo=black,CouleurSous=red,CouleurSymbole=orange,Verification=false,Nombre=0,Egalite=false,Produit=false,Facteurs=false,Carre=false,Exact=false,Pose=false,Equivalence=false}

\newcommand\rightcomment[4]{%
  \begin{tikzpicture}[remember picture,overlay]
    \draw[Cfleches,-stealth]
    ($({pic cs:#3}|-{pic cs:#1})+(\useKV[ClesEquation]{Ecart},0)$)
    .. controls +(0.2,-0.05) and +(0.2,0.1) ..
    node[right,align=left]{#4}
    ($({pic cs:#3}|-{pic cs:#2})+(\useKV[ClesEquation]{Ecart},0.1)$);
  \end{tikzpicture}%
}%

\newcommand\leftcomment[4]{%
  \begin{tikzpicture}[remember picture,overlay]
    \draw[Cfleches,-stealth]
    ($({pic cs:#3}|-{pic cs:#1})-(\useKV[ClesEquation]{Ecart},0)$)
    .. controls +(-0.2,-0.05) and +(-0.2,0.1) ..
    node[left,align=right]{#4}
    ($({pic cs:#3}|-{pic cs:#2})-(\useKV[ClesEquation]{Ecart},-0.1)$);
  \end{tikzpicture}%
}%

\newcommand\Rightcomment[4]{%
  \begin{tikzpicture}[remember picture,overlay]
    \draw[Cfleches,-stealth]
    ($({pic cs:#3}|-{pic cs:#1})+(\useKV[ClesEquation]{Ecart},0)$)
    .. controls +(0.2,-0.05) and +(0.2,0.1) ..
    node[right,align=left]{#4}
    ($({pic cs:#3}|-{pic cs:#2})+(\useKV[ClesEquation]{Ecart},0.1)$);
  \end{tikzpicture}%
}%
\newcommand\Leftcomment[4]{%
  \begin{tikzpicture}[remember picture,overlay]
    \draw[Cfleches,-stealth]
    ($({pic cs:#3}|-{pic cs:#1})-(\useKV[ClesEquation]{Ecart},0)$)
    .. controls +(-0.2,-0.05) and +(-0.2,0.1) ..
    node[left,align=right]{#4}
    ($({pic cs:#3}|-{pic cs:#2})-(\useKV[ClesEquation]{Ecart},-0.1)$);
  \end{tikzpicture}%
}%

% Pour "oublier" les tikzmarks. En cas de plusieurs utilisations de la macro \ResolEquation
\newcounter{Nbequa}
\setcounter{Nbequa}{0}

%CT
\newdimen\fdashwidth\fdashwidth  = 0.8pt % \'epaisseur traits
\newdimen\fdashlength\fdashlength = 0.5mm % longueur des pointill\'es et s\'eparation entre pointill\'es
\newdimen\fdashsep\fdashsep    = 3pt % s\'eparateur entre contenu et traits

\def\fdash#1{%
  \leavevmode\begingroup%
  \setbox0\hbox{#1}%
  \def\hdash{\vrule height\fdashwidth width\fdashlength\relax}%
  \def\vdash{\hrule height\fdashlength width\fdashwidth\relax}%
  \def\dashblank{\kern\fdashlength}%
  \ifdim\fdashsep>0pt%
  \setbox0\hbox{\vrule width0pt height\dimexpr\ht0+\fdashsep depth\dimexpr\dp0+\fdashsep\kern\fdashsep\unhbox0 \kern\fdashsep}%
  \fi%
  \edef\hdash{\hbox to\the\wd0{\noexpand\color{Csymbole}\hdash\kern.5\fdashlength\xleaders\hbox{\hdash\dashblank}\hfil\hdash}}%
  \edef\vdash{\vbox to\the\dimexpr\ht0+\dp0+2\fdashwidth{\noexpand\color{Csymbole}\vdash\kern.5\fdashlength\xleaders\vbox{\vdash\dashblank}\vfil\vdash}}%
  \hbox{%
    \vdash%
    \vtop{\vbox{\offinterlineskip\hdash\hbox{\unhbox0 }\hdash}}%
    \vdash}%
  \endgroup%
}%
% fin CT
\def\Fdash#1{\raisebox{-2\fdashsep+\fdashwidth}{\fdash{#1}}}%

%Une simplification de a/b est possible ou non ?
\newboolean{Simplification}

\newcommand\SSimpliTest[2]{%
  % Test d'une simplification possible ou pas de #1/#2
  \newcount\numerateur\newcount\denominateur\newcount\valabsnum\newcount\valabsdeno%
  \numerateur=\number#1
  \denominateur=\number#2
  \ifnum\number#1<0
  \valabsnum=\numexpr0-\number#1
  \else
  \valabsnum=\number#1
  \fi
  \ifnum\number#2<0
  \valabsdeno=\numexpr0-\number#2
  \else
  \valabsdeno=\number#2
  \fi
  \ifnum\the\valabsnum=0
    \setboolean{Simplification}{true}
  \else
    \PGCD{\the\valabsnum}{\the\valabsdeno}
    \ifnum\pgcd>1
      \setboolean{Simplification}{true}
    \else
      \ifnum\the\numerateur<0
        \ifnum\the\denominateur<0
          \setboolean{Simplification}{true}
        \else
          \ifnum\valabsdeno=1\relax
            \setboolean{Simplification}{true}
          \else
          \setboolean{Simplification}{false}
          \fi
        \fi
      \else
        \ifnum\valabsdeno=1\relax
          \setboolean{Simplification}{true}
        \else
          \setboolean{Simplification}{false}
        \fi
      \fi
    \fi
  \fi
}

\definecolor{Cfleches}{RGB}{100,100,100}%

\newcommand\AffichageEqua[4]{%
  \def\LETTRE{\useKV[ClesEquation]{Lettre}}%
  \ensuremath{%
    % partie du x
    \xintifboolexpr{#1==0}{}{\xintifboolexpr{#1==1}{}{\xintifboolexpr{#1==-1}{-}{\num{#1}}}\LETTRE}%
    % partie du nombre
    \xintifboolexpr{#2==0}{\xintifboolexpr{#1==0}{0}{}}{\xintifboolexpr{#2>0}{\xintifboolexpr{#1==0}{}{+}\num{#2}}{\num{#2}}}%
    % egal
    =
    % partie du x
    \xintifboolexpr{#3==0}{}{\xintifboolexpr{#3==1}{}{\xintifboolexpr{#3==-1}{-}{\num{#3}}}\LETTRE}%
    % partie du nombre
    \xintifboolexpr{#4==0}{%
      \xintifboolexpr{#3==0}{0}{}
    }{%
      \xintifboolexpr{#4>0}{\xintifboolexpr{#3==0}{}{+}\num{#4}}{\num{#4}}%
    }
  }%
}%

\newcommand\EcrireSolutionEquation[4]{%
  L'équation \AffichageEqua{#1}{#2}{#3}{#4} a une unique solution : \opdiv*{\Coeffb}{\Coeffa}{solution}{resteequa}\opcmp{resteequa}{0}$\ifboolKV[ClesEquation]{LettreSol}{\useKV[ClesEquation]{Lettre}=}{}\displaystyle\ifopeq\opexport{solution}{\solution}\num{\solution}\else\ifboolKV[ClesEquation]{Entier}{\SSimplifie{\Coeffb}{\Coeffa}}{\frac{\num{\Coeffb}}{\num{\Coeffa}}}\fi$.
}%

\input{PfCEquationSoustraction2}%
\input{PfCEquationTerme1}%
\input{PfCEquationComposition2}%
\input{PfCEquationPose1}%
\input{PfCEquationSymbole1}%
\input{PfCEquationLaurent1}

\newcommand\ResolEquation[5][]{%
  \useKVdefault[ClesEquation]%
  \setKV[ClesEquation]{#1}%
  \colorlet{Cterme}{\useKV[ClesEquation]{CouleurTerme}}%
  \colorlet{Ccompo}{\useKV[ClesEquation]{CouleurCompo}}%
  \colorlet{Csymbole}{\useKV[ClesEquation]{CouleurSymbole}}%
  \colorlet{Cdecomp}{\useKV[ClesEquation]{CouleurSous}}%
  \ifboolKV[ClesEquation]{Carre}{%
    \ResolEquationCarre[#1]{#2}%
  }{%
    \ifboolKV[ClesEquation]{Produit}{%
      \ResolEquationProduit[#1]{#2}{#3}{#4}{#5}%
    }{%
      \ifboolKV[ClesEquation]{Verification}{%
        \Verification[#1]{#2}{#3}{#4}{#5}%
      }{%
        \ifboolKV[ClesEquation]{Symbole}{%
          \ResolEquationSymbole[#1]{#2}{#3}{#4}{#5}%
        }{%
          \ifboolKV[ClesEquation]{Laurent}{%
            \ResolEquationLaurent[#1]{#2}{#3}{#4}{#5}%
          }{%
            \ifboolKV[ClesEquation]{Terme}{%
              \ResolEquationTerme[#1]{#2}{#3}{#4}{#5}%
            }{\ifboolKV[ClesEquation]{Composition}{%
                \ResolEquationComposition[#1]{#2}{#3}{#4}{#5}%
              }{\ifboolKV[ClesEquation]{Pose}{%
                  \ResolEquationL[#1]{#2}{#3}{#4}{#5}%
                }{%
                  \ResolEquationSoustraction[#1]{#2}{#3}{#4}{#5}%
                }%
              }%
            }%
          }%
        }%
      }%
    }%
  }%
}%

\newcommand\ResolEquationCarre[2][]{%
  \setKV[ClesEquation]{#1}%
  \xintifboolexpr{#2<0}{%
    Comme $\num{#2}$ est n\'egatif, alors l'\'equation $\useKV[ClesEquation]{Lettre}^2=\num{#2}$ n'a aucune solution.%
  }{\xintifboolexpr{#2==0}{%
      L'\'equation $\useKV[ClesEquation]{Lettre}^2=0$ a une unique solution : $\useKV[ClesEquation]{Lettre}=0$.%
    }{%
      Comme \num{#2} est positif, alors l'\'equation $\useKV[ClesEquation]{Lettre}^2=\num{#2}$ a deux solutions :%
      \begin{align*}
        \useKV[ClesEquation]{Lettre}&=\sqrt{\num{#2}}&&\text{et}&\useKV[ClesEquation]{Lettre}&=-\sqrt{\num{#2}}%\\
        \ifboolKV[ClesEquation]{Exact}{\\%
        \useKV[ClesEquation]{Lettre}&=\num{\fpeval{sqrt(#2)}}&&\text{et}&\useKV[ClesEquation]{Lettre}&=-\num{\fpeval{sqrt(#2)}}}{}%
      \end{align*}
    }%
  }%
}%

\newcommand\ResolEquationProduit[5][]{%
  \setKV[ClesEquation]{#1}%
  \ifboolKV[ClesEquation]{Equivalence}{}{C'est un produit nul donc \ifboolKV[ClesEquation]{Facteurs}{l'un au
      moins des facteurs est nul}{} :}%
  \ifboolKV[ClesEquation]{Equivalence}{%
          \[\Distri{#2}{#3}{#4}{#5}=0\]
    \begin{align*}%
      &\makebox[0pt]{$\Longleftrightarrow$}&\xintifboolexpr{#3==0}{\xintifboolexpr{#2==1}{}{\num{#2}}\useKV[ClesEquation]{Lettre}}{\xintifboolexpr{#2==1}{}{\num{#2}}\useKV[ClesEquation]{Lettre}\xintifboolexpr{#3>0}{+\num{#3}}{-\num{\fpeval{0-#3}}}}&=0&\quad&\makebox[0pt]{ou}\quad&\xintifboolexpr{#5==0}{\xintifboolexpr{#4==1}{}{\num{#4}}\useKV[ClesEquation]{Lettre}}{\xintifboolexpr{#4==1}{}{\num{#4}}\useKV[ClesEquation]{Lettre}\xintifboolexpr{#5>0}{+\num{#5}}{-\num{\fpeval{0-#5}}}}&=0\\
      &\makebox[0pt]{$\Longleftrightarrow$}&\xintifboolexpr{#3==0}{\xdef\Coeffa{1}\xdef\Coeffb{\fpeval{0-#3}}\xintifboolexpr{#2==1}{&}{\useKV[ClesEquation]{Lettre}&=0}}{\xdef\Coeffa{#2}\xdef\Coeffb{\fpeval{0-#3}}\xintifboolexpr{\Coeffa==1}{}{\num{\Coeffa}}\useKV[ClesEquation]{Lettre}&=\num{\Coeffb}}&&&\xintifboolexpr{#5==0}{\xdef\Coeffc{1}\xdef\Coeffd{\fpeval{0-#5}}\xintifboolexpr{#4==1}{&}{\useKV[ClesEquation]{Lettre}&=0}}{\xdef\Coeffc{#4}\xdef\Coeffd{\fpeval{0-#5}}\xintifboolexpr{\Coeffc==1}{}{\num{\Coeffc}}\useKV[ClesEquation]{Lettre}&=\num{\Coeffd}}%\\
      \xintifboolexpr{\Coeffa==1 'and' \Coeffc==1}{}{\\%\ifnum\cmtd>1
      &\makebox[0pt]{$\Longleftrightarrow$}&\xintifboolexpr{\Coeffa==1}{&}{\useKV[ClesEquation]{Lettre}&=\frac{\num{\Coeffb}}{\num{\Coeffa}}}\xintifboolexpr{\Coeffc==1}{}{&&&\useKV[ClesEquation]{Lettre}&=\frac{\num{\Coeffd}}{\num{\Coeffc}}}
      % accolade%\\
      %%%% 
      \ifboolKV[ClesEquation]{Entier}{%
      \xdef\TSimp{}%
      \SSimpliTest{\Coeffb}{\Coeffa}\ifthenelse{\boolean{Simplification}}{\xintifboolexpr{#3==0}{\xdef\TSimp{0}}{\xdef\TSimp{1}}}{\xdef\TSimp{0}}
      \SSimpliTest{\Coeffd}{\Coeffc}\ifthenelse{\boolean{Simplification}}{\xintifboolexpr{#5==0}{}{\xdef\TSimp{\fpeval{\TSimp+1}}}}{}
      \xintifboolexpr{\TSimp==0}{}{\\
      \ifboolKV[ClesEquation]{Simplification}{%
      &\makebox[0pt]{$\Longleftrightarrow$}&\SSimpliTest{\Coeffb}{\Coeffa}\xintifboolexpr{\Coeffa==1}{&}{\ifthenelse{\boolean{Simplification}}{\useKV[ClesEquation]{Lettre}&=\SSimplifie{\Coeffb}{\Coeffa}}{&}%\\
      }
      }{}
      &&&\ifboolKV[ClesEquation]{Simplification}{%
      \SSimpliTest{\Coeffd}{\Coeffc}%
          \xintifboolexpr{\Coeffc==1}{}{\ifthenelse{\boolean{Simplification}}{\useKV[ClesEquation]{Lettre}&=\SSimplifie{\Coeffd}{\Coeffc}}{}%\\
      }
      }{}
      }
      }{}
      }
    \end{align*}
  }{%
    \begin{align*}
    \xintifboolexpr{#3==0}{\xintifboolexpr{#2==1}{}{\num{#2}}\useKV[ClesEquation]{Lettre}}{\xintifboolexpr{#2==1}{}{\num{#2}}\useKV[ClesEquation]{Lettre}\xintifboolexpr{#3>0}{+\num{#3}}{-\num{\fpeval{0-#3}}}}&=0&&\text{ou}&\xintifboolexpr{#5==0}{\xintifboolexpr{#4==1}{}{\num{#4}}\useKV[ClesEquation]{Lettre}}{\xintifboolexpr{#4==1}{}{\num{#4}}\useKV[ClesEquation]{Lettre}\xintifboolexpr{#5>0}{+\num{#5}}{-\num{\fpeval{0-#5}}}}&=0\\
    \xintifboolexpr{#3==0}{\xdef\Coeffa{1}\xdef\Coeffb{\fpeval{0-#3}}\xintifboolexpr{#2==1}{&}{\useKV[ClesEquation]{Lettre}&=0}}{\xdef\Coeffa{#2}\xdef\Coeffb{\fpeval{0-#3}}\xintifboolexpr{\Coeffa==1}{}{\num{\Coeffa}}\useKV[ClesEquation]{Lettre}&=\num{\Coeffb}}&&&\xintifboolexpr{#5==0}{\xdef\Coeffc{1}\xdef\Coeffd{\fpeval{0-#5}}\xintifboolexpr{#4==1}{&}{\useKV[ClesEquation]{Lettre}&=0}}{\xdef\Coeffc{#4}\xdef\Coeffd{\fpeval{0-#5}}\xintifboolexpr{\Coeffc==1}{}{\num{\Coeffc}}\useKV[ClesEquation]{Lettre}&=\num{\Coeffd}}%\\
      \xintifboolexpr{\Coeffa==1 'and' \Coeffc==1}{}{\\%\ifnum\cmtd>1
      \xintifboolexpr{\Coeffa==1}{&}{\useKV[ClesEquation]{Lettre}&=\frac{\num{\Coeffb}}{\num{\Coeffa}}}\xintifboolexpr{\Coeffc==1}{}{&&&\useKV[ClesEquation]{Lettre}&=\frac{\num{\Coeffd}}{\num{\Coeffc}}}
       %accolade%\\
      %%%%   
      \ifboolKV[ClesEquation]{Entier}{%
      \xdef\TSimp{}
      \SSimpliTest{\Coeffb}{\Coeffa}\ifthenelse{\boolean{Simplification}}{\xintifboolexpr{#3==0}{\xdef\TSimp{0}}{\xdef\TSimp{1}}}{\xdef\TSimp{0}}
      \SSimpliTest{\Coeffd}{\Coeffc}\ifthenelse{\boolean{Simplification}}{\xintifboolexpr{#5==0}{}{\xdef\TSimp{\fpeval{\TSimp+1}}}}{}
      \xintifboolexpr{\TSimp==0}{}{\\
      \ifboolKV[ClesEquation]{Simplification}{%
      \SSimpliTest{\Coeffb}{\Coeffa}
      \xintifboolexpr{\Coeffa==1}{&}{\ifthenelse{\boolean{Simplification}}{\useKV[ClesEquation]{Lettre}&=\SSimplifie{\Coeffb}{\Coeffa}}{&}%\\
      }
      }{}
      &&&\ifboolKV[ClesEquation]{Simplification}{%
      \SSimpliTest{\Coeffd}{\Coeffc}%
          \xintifboolexpr{\Coeffc==1}{}{\ifthenelse{\boolean{Simplification}}{\useKV[ClesEquation]{Lettre}&=\SSimplifie{\Coeffd}{\Coeffc}}{}%\\
      }
      }{}
      }
      }{}
      }
    \end{align*}
  }%
  \ifboolKV[ClesEquation]{Solution}{L'\'equation $\xintifboolexpr{#3==0}{\xintifboolexpr{#2==1}{}{\num{#2}}\useKV[ClesEquation]{Lettre}}{(\xintifboolexpr{#2==1}{}{\num{#2}}\useKV[ClesEquation]{Lettre}\xintifboolexpr{#3>0}{+\num{#3}}{-\num{\fpeval{0-#3}}})}\xintifboolexpr{#5==0}{\times\xintifboolexpr{#4==1}{}{\num{#4}}\useKV[ClesEquation]{Lettre}}{(\xintifboolexpr{#4==1}{}{\num{#4}}\useKV[ClesEquation]{Lettre}\xintifboolexpr{#5>0}{+\num{#5}}{-\num{\fpeval{0-#5}}})}=0$ a deux solutions : \opdiv*{\Coeffb}{\Coeffa}{solution}{resteequa}\opcmp{resteequa}{0}$\ifboolKV[ClesEquation]{LettreSol}{\useKV[ClesEquation]{Lettre}=}{}\displaystyle\ifopeq\opexport{solution}{\solution}\num{\solution}\else\ifboolKV[ClesEquation]{Entier}{\SSimplifie{\Coeffb}{\Coeffa}}{\frac{\num{\Coeffb}}{\num{\Coeffa}}}\fi$ et \opdiv*{\Coeffd}{\Coeffc}{solution}{resteequa}\opcmp{resteequa}{0}$\ifboolKV[ClesEquation]{LettreSol}{\useKV[ClesEquation]{Lettre}=}{}\displaystyle\ifopeq\opexport{solution}{\solution}\num{\solution}\else\ifboolKV[ClesEquation]{Entier}{\SSimplifie{\Coeffd}{\Coeffc}}{\frac{\num{\Coeffd}}{\num{\Coeffc}}}\fi$.
  }{}%
}

\newcommand\Verification[5][]{%
  \setKV[ClesEquation]{#1}%
  \xdef\ValeurTest{\useKV[ClesEquation]{Nombre}}%
  Testons la valeur $\useKV[ClesEquation]{Lettre}=\num{\ValeurTest}$ :%
  \begin{align*}
    \xintifboolexpr{#2==0}{\num{#3}}{\num{#2}\times\xintifboolexpr{\ValeurTest<0}{(\num{\ValeurTest})}{\num{\ValeurTest}}\xintifboolexpr{#3==0}{}{\xintifboolexpr{#3>0}{+\num{#3}}{\num{#3}}}}&&\xintifboolexpr{#4==0}{\num{#5}}{\num{#4}\times\xintifboolexpr{\ValeurTest<0}{(\num{\ValeurTest})}{\num{\ValeurTest}}\xintifboolexpr{#5==0}{}{\xintifboolexpr{#5>0}{+\num{#5}}{\num{#5}}}}\\
    \xintifboolexpr{#2==0}{}{\num{\fpeval{#2*\useKV[ClesEquation]{Nombre}}}\xintifboolexpr{#3==0}{}{\xintifboolexpr{#3>0}{+\num{#3}}{\num{#3}}}}&&\xintifboolexpr{#4==0}{}{\num{\fpeval{#4*\useKV[ClesEquation]{Nombre}}}\xintifboolexpr{#5==0}{}{\xintifboolexpr{#5>0}{+\num{#5}}{\num{#5}}}}\\
    \xintifboolexpr{#2==0}{}{\num{\fpeval{#2*\useKV[ClesEquation]{Nombre}+#3}}}&&\xintifboolexpr{#4==0}{}{\num{\fpeval{#4*\useKV[ClesEquation]{Nombre}+#5}}}
  \end{align*}
  \xdef\Testa{\fpeval{#2*\useKV[ClesEquation]{Nombre}+#3}}\xdef\Testb{\fpeval{#4*\useKV[ClesEquation]{Nombre}+#5}}%
  \ifboolKV[ClesEquation]{Egalite}{%
    Comme \xintifboolexpr{\Testa==\Testb}{$\num{\Testa}=\num{\Testb}$}{$\num{\Testa}\not=\num{\Testb}$}, alors l'\'egalit\'e $\xintifboolexpr{#2==0}{\num{#3}}{\xintifboolexpr{#2==1}{}{\num{#2}}\useKV[ClesEquation]{Lettre}\xintifboolexpr{#3==0}{}{\xintifboolexpr{#3>0}{+\num{#3}}{-\num{\fpeval{0-#3}}}}}=\xintifboolexpr{#4==0}{\num{#5}}{\xintifboolexpr{#4==1}{}{\num{#4}}\useKV[ClesEquation]{Lettre}\xintifboolexpr{#5==0}{}{\xintifboolexpr{#5>0}{+\num{#5}}{-\num{\fpeval{0-#5}}}}}$ \xintifboolexpr{\Testa==\Testb}{ est v\'erifi\'ee }{ n'est pas v\'erifi\'ee } pour $\useKV[ClesEquation]{Lettre}=\num{\useKV[ClesEquation]{Nombre}}$.%
  }{\xintifboolexpr{\Testa==\Testb}{Comme $\num{\Testa}=\num{\Testb}$, alors $\useKV[ClesEquation]{Lettre}=\num{\useKV[ClesEquation]{Nombre}}$ est bien }{Comme $\num{\Testa}\not=\num{\Testb}$, alors $\useKV[ClesEquation]{Lettre}=\num{\useKV[ClesEquation]{Nombre}}$ n'est pas }une solution de l'\'equation $\xintifboolexpr{#2==0}{\num{#3}}{\xintifboolexpr{#2==1}{}{\num{#2}}\useKV[ClesEquation]{Lettre}\xintifboolexpr{#3==0}{}{\xintifboolexpr{#3>0}{+\num{#3}}{-\num{\fpeval{0-#3}}}}}=\xintifboolexpr{#4==0}{\num{#5}}{\xintifboolexpr{#4==1}{}{\num{#4}}\useKV[ClesEquation]{Lettre}\xintifboolexpr{#5==0}{}{\xintifboolexpr{#5>0}{+\num{#5}}{-\num{\fpeval{0-#5}}}}}$.}%
}%